The overall stability constant of the complex ion $\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}$ is $2.1 \times 10^{13}$. The overall dissociation constant is $\mathrm{y} \times 10^{-14}$. Then y is $\_\_\_\_$. (Nearest integer)

JEE Main · 2021 · 26 Aug 2021 · Shift 2 · Coordination Compounds

The overall stability constant of the complex ion

[Cu (NH_{3})_{4}]^{2 +}

2.1 \times 1 0^{13}

. The overall dissociation constant is

y \times 1 0^{- 14}

. Then y is

____

. (Nearest integer)

Answer: 5

Solution

Formation and dissociation of the complex ion are the reverse of each other, so the overall dissociation constant is the reciprocal of the overall stability constant:

K_{d} = \frac{1}{β} = \frac{1}{2.1 \times 1 0 ^{13}} = 4.76 \times 1 0^{- 14}

Comparing with

y \times 1 0^{- 14}

gives

y = 4.76

, so

y

to the nearest integer is

5

JEE Main · 2021 · 26 Aug 2021 · Shift 2 · Integer answer

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