For the circuit shown below, calculate the value of $\mathrm{I}_{2}$ :

JEE Main · 2021 · 20 Jul 2021 · Shift 1 · Current Electricity

For the circuit shown below, calculate the value of

I_{2}

Answer: (C)

The zener is in breakdown, so it holds

50

V across itself and across the parallel load. The whole supply current passes through the series resistance:

I_{S} = \frac{V _{i} - V _{Z}}{R _{S}} = \frac{100 - 50}{1000} = 50 mA

The load draws

I_{L} = \frac{V _{Z}}{R} = \frac{50}{2000} = 25 mA

. What the series resistance delivers but the load does not take flows through the zener, so

I_{Z} = 50 - 25 = 25 mA

JEE Main · 2021 · 20 Jul 2021 · Shift 1 · Single correct option