100 ml of $0.0018 \%(\mathrm{w} / \mathrm{v})$ solution of $\mathrm{Cl}^{-}$ion was the minimum concentration of $\mathrm{Cl}^{-}$required to precipitate a negative sol in one h . The coagulating value of $\mathrm{Cl}^{-}$ion is \_\_\_\_ . (Nearest integer)

JEE Main · 2021 · 20 Jul 2021 · Shift 2 · Surface Chemistry

100 ml of

0.0018% (w / v)

solution of

Cl^{-}

ion was the minimum concentration of

Cl^{-}

required to precipitate a negative sol in one h . The coagulating value of

Cl^{-}

ion is ____ . (Nearest integer)

Answer: 1

Solution

A solution that is

0.0018%

(w/v) holds 0.0018 g of chloride in 100 mL, that is 0.018 g in one litre. Dividing by the molar mass 35.5 g mol

^{- 1}

gives

c = \frac{0.018}{35.5} = 5.07 \times 1 0^{- 4} mol L^{- 1} = 0.507 millimol L^{- 1}

The coagulating value is this minimum concentration needed to coagulate the sol, expressed in millimoles per litre, so to the nearest integer it is 1.

JEE Main · 2021 · 20 Jul 2021 · Shift 2 · Integer answer

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