If the concentration of glucose ($\ce{C6H12O6}$) in blood is $0.72 \text{ g L}^{-1}$, the molarity of glucose in blood is ______ $\times 10^{-3} \text{ M}$. (Nearest integer) (Given: Atomic mass of $\ce{C}=12$, $\ce{H}=1$, $\ce{O}=16$ u)

JEE Main · 2021 · 22 Jul 2021 · Shift 2 · Some Basic Concepts of Chemistry

If the concentration of glucose (

C X_{6} H X_{12} O X_{6}

) in blood is

0.72 g L^{- 1}

, the molarity of glucose in blood is ______

\times 1 0^{- 3} M

. (Nearest integer)
(Given: Atomic mass of

C = 12

H = 1

O = 16

Answer: 4

The molar mass of glucose is

6 (12) + 12 (1) + 6 (16) = 180 g mo l^{- 1}

. One litre of blood holds 0.72 g of glucose, so the amount of glucose in that litre is

n = \frac{0.72}{180} = 4 \times 1 0^{- 3} mol

Since this is the amount in one litre, the molarity of glucose in blood is

4 \times 1 0^{- 3}

JEE Main · 2021 · 22 Jul 2021 · Shift 2 · Integer answer