The type of hybridisation and magnetic property of the complex $\left[\mathrm{MnCl}_{6}\right]^{3-}$, respectively, are:

(A) $sp^{3} d^{2}$ and paramagnetic

(B) $d^{2} \mathrm{sp}^{3}$ and paramagnetic

(C) $d^{2} sp^{3}$ and diamagnetic

(D) $\mathrm{sp}^{3} \mathrm{~d}^{2}$ and diamagnetic

JEE Main · 2021 · 27 Jul 2021 · Shift 1 · Coordination Compounds

The type of hybridisation and magnetic property of the complex

[MnCl_{6}]^{3 -}

, respectively, are:

(A) $s p^{3} d^{2}$ and paramagnetic✓ Correct
(B) $d^{2} sp^{3}$ and paramagnetic
(C) $d^{2} s p^{3}$ and diamagnetic
(D) $sp^{3} d^{2}$ and diamagnetic

Answer: (A)

Solution

Mn

has electronic configuration

[Ar] 3 d^{5} 4 s^{2}

. In

[MnCl_{6}]^{3 -}

, Mn is in +3 oxidation state with configuration

3 d^{4}

Cl^{-}

is a weak field ligand, so no pairing occurs. The

3 d^{4}

configuration remains as

t_{2 g}^{3} e_{g}^{1}

with 4 unpaired electrons.

The complex is octahedral with outer orbital hybridization

s p^{3} d^{2}

(using 4s, 4p, and 4d orbitals). With unpaired electrons present, the complex is paramagnetic.

JEE Main · 2021 · 27 Jul 2021 · Shift 1 · Single correct option

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