Given below are two statements:
Statement I : and ared hybridised
Statement II : and are paramagnetic and have 4 and 5 unpaired electrons, respectively.
In the light of the above statements, choose the correct answer from the options given below:
Statement I : and ared hybridised
Statement II : and are paramagnetic and have 4 and 5 unpaired electrons, respectively.
In the light of the above statements, choose the correct answer from the options given below:
- (A)Statement I is correct but Statement II is false
- (B)Both Statement I and Statement II are false
- (C)Statement I is incorrect but Statement II is true
- (D)Both Statement I and Statement II are true✓ Correct
Answer: (D)
Solution
Cyanide is a strong field ligand, so in the and in the pair their electrons within the set; oxalate does the same for the in . Pairing empties two inner orbitals in each case, which are then used for bonding, so all three are hybridised and the first statement holds. Chloride and fluoride are weak field ligands and force no pairing, so keeps the four unpaired electrons of and the five unpaired electrons of , making both paramagnetic as described. Both Statement I and Statement II are true.
JEE Main · 2021 · 27 Jul 2021 · Shift 2 · Single correct option