Question

Match List-I with List-II

List - I (Colloid Preparation method)
(a) Hydrolysis
(b) Reduction
(c) Oxidation
(d) Double Decomposition

List - II (Chemical Reaction)
(i) $2 \mathrm{AuCl}_{3}+3 \mathrm{HCHO}+3 \mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{Au}(\mathrm{sol})+3 \mathrm{HCOOH}+6 \mathrm{HCl}$
(ii) $\mathrm{As}_{2} \mathrm{O}_{3}+3 \mathrm{H}_{2} \mathrm{~S} \rightarrow \mathrm{As}_{2} \mathrm{S}_{3}(\mathrm{sol})+3 \mathrm{H}_{2} \mathrm{O}$
(iii) $\mathrm{SO}_{2}+2 \mathrm{H}_{2} \mathrm{~S} \rightarrow 3 \mathrm{~S}(\mathrm{sol})+2 \mathrm{H}_{2} \mathrm{O}$
(iv) $\mathrm{FeCl}_{3}+3 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{Fe}(\mathrm{OH})_{3}(\mathrm{sol})+3 \mathrm{HCl}$

Choose the most appropriate answer from the options given below:

Accepted Answer

Hydrolysis of by water gives the sol. Reduction of by formaldehyde gives the gold sol. Oxidation of by gives the sulfur sol. Double decomposition of with gives the sol. Hydrolysis matches the ferric chloride reaction, reduction the gold reaction, oxidation the sulfur reaction, and double decomposit…

JEE Main · 2021 · 01 Sep 2021 · Shift 2 · Surface Chemistry

Solution

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