The number of possible optical isomers for the complexes $\mathrm{MA}_{2} \mathrm{~B}_{2}$ with $\mathrm{sp}^{3}$ and $\mathrm{dsp}^{2}$ hybridized metal atom, respectively is: [Note: A and B are unidentate neutral and unidentate monoanionnic ligands, respectively]

JEE Main · 2020 · 07 Jan 2020 · Shift 2 · Coordination Compounds

The number of possible optical isomers for the complexes

MA_{2} B_{2}

with

sp^{3}

and

dsp^{2}

hybridized metal atom, respectively is:
[Note: A and B are unidentate neutral and unidentate monoanionnic ligands, respectively]

(A)2 and 2
(B)0 and 2
(C)0 and 1
(D)0 and 0✓ Correct

Answer: (D)

Solution

For a tetrahedral

MA X_{2} B X_{2}

built on

s p^{3}

the molecule has a mirror plane, so it is achiral and shows no optical isomers. For a square-planar

MA X_{2} B X_{2}

built on

d s p^{2}

the cis and trans forms each also possess a plane of symmetry, so again there are no optical isomers. The count is therefore zero and zero.

JEE Main · 2020 · 07 Jan 2020 · Shift 2 · Single correct option

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