JEE Main · 2020 · 08 Jan 2020 · Shift 1 · Heat & Thermodynamics

Reading the cycle off the given $V\text{-}T$ diagram, the step $x\to y$ is an expansion at constant temperature, so on a $P\text{-}V$ diagram it is a falling hyperbola as the pressure drops. The step $y\to z$ keeps the volume fixed while the temperature rises, which on the $P\text{-}V$ plane is a vertical line of increasing pressure. The closing step $z\to x$ brings both volume and temperature down together, tracing a line back to the starting state. Applying $PV=nRT$ to each leg, the pressure-volume picture is a decreasing isotherm, then a vertical pressure rise at constant volume, then a straight return to the initial point.