JEE Main · 2020 · 09 Jan 2020 · Shift 2 · Current Electricity

The current i in the network is:

(A)0.6 A
(B)0 A
(C)0.2 A
(D)0.3 A✓ Correct

Answer: (D)

Solution

Both diodes in the network are reverse biased, so each behaves as an open switch and carries no current, forcing the current through the remaining resistive path alone. With that path presenting an effective

30 Ω

across the

9 V

supply, Ohm's law gives

i = \frac{9}{30} = 0.3 A

JEE Main · 2020 · 09 Jan 2020 · Shift 2 · Single correct option

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