On heating, lead (II) nitrate gives a brown gas (A). The gas (A) on cooling changes to a colourless solid/liquid (B). (B) on heating with NO changes to a blue solid (C). The oxidation number of nitrogen in solid (C) is:
- (A)+4
- (B)+3✓ Correct
- (C)+2
- (D)+5
Answer: (B)
Solution
Heating lead(II) nitrate gives the brown gas (A): . On cooling this dimerises to the colourless (B). Warming with produces the blue solid (C): . In the two nitrogen atoms share the oxidation state .
JEE Main · 2020 · 04 Sep 2020 · Shift 1 · Single correct option