JEE Main · 2020 · 04 Sep 2020 · Shift 1 · Redox Reactions and Electrochemistry

WhatsApp Email
On heating, lead (II) nitrate gives a brown gas (A). The gas (A) on cooling changes to a colourless solid/liquid (B). (B) on heating with NO changes to a blue solid (C). The oxidation number of nitrogen in solid (C) is:
  1. (A)+4
  2. (B)+3✓ Correct
  3. (C)+2
  4. (D)+5

Answer: (B)

Solution

Heating lead(II) nitrate gives the brown gas (A): . On cooling this dimerises to the colourless (B). Warming with produces the blue solid (C): . In the two nitrogen atoms share the oxidation state .

JEE Main · 2020 · 04 Sep 2020 · Shift 1 · Single correct option

More JEE Main questions on Redox Reactions and Electrochemistry

  1. The pH and conductance of a weak acid (HX) was found to be 5 and , respectively. The conductance was measured under standard condition using a cell where the electrode plates having a surface area of were at a distance of 15 cm a …
    JEE Main 2026View solution →
  2. Consider the following electrochemical cell at 298 K
    .
    If the reaction quotient at a giv …
    JEE Main 2026View solution →
  3. Aqueous HCl reacts with to form , and . What is the weight (in g) of liberated when 8.7 g of is reacted w …
    JEE Main 2026View solution →
  4. For a closed circuit Daniell cell, which of the following plots is the accurate one at a given temperature?
    JEE Main 2026View solution →
  5. MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K
    ;
    If the standard reduction potential for …
    JEE Main 2026View solution →
  6. Consider the following reduction processes:

    …
    JEE Main 2026View solution →