JEE Main · 2019 · 08 Apr 2019 · Shift 2 · Kinematics

Starting from rest with constant acceleration, look at what each quantity does. The acceleration stays constant, so its graph against time is a horizontal line, which matches graph a. The velocity grows as $v=at$, a straight line through the origin, matching graph b. The displacement goes as $x=\frac{1}{2}a{t}^2$, a parabola opening upward, matching graph d. The one that does not fit is the velocity plotted against displacement: from $v^2=2ax$ we get $v\propto \sqrt{x}$, which is not a straight line, so graph c is wrong. Hence the motion is correctly shown by a, b and d.