The strength of 11.2 volume solution of $\mathrm{H}_{2} \mathrm{O}_{2}$ is: [Given that molar mass of $\mathrm{H}=1 \mathrm{~g} \mathrm{~mol}^{-1}$ and $\mathrm{O}=16 \mathrm{~g} \mathrm{~mol}^{-1}$]

JEE Main · 2019 · 08 Apr 2019 · Shift 2 · Some Basic Concepts of Chemistry

The strength of 11.2 volume solution of

H_{2} O_{2}

is:
[Given that molar mass of

H = 1 g mol^{- 1}

and

O = 16 g mol^{- 1}

]

Answer: (A)

Volume strength tells us how many litres of

O X_{2}

at STP one litre of solution can release. From

2 H X_{2} O X_{2} 2 H X_{2} O + O X_{2}

, two moles of

H X_{2} O X_{2}

, that is

68 g

, give

22.4 L

O X_{2}

. An 11.2 volume solution releases

11.2 L

O X_{2}

per litre, which needs

\frac{68 \times 11.2}{22.4} = 34 g

H X_{2} O X_{2}

in that litre. Taking the litre of solution as about

1000 g

, the percentage strength is

\frac{34}{1000} \times 100 = 3.4%

JEE Main · 2019 · 08 Apr 2019 · Shift 2 · Single correct option