Determine the charge on the capacitor in the following circuit:
(A)200μC✓ Correct
(B)60μC
(C)10μC
(D)2μC
Answer: (A)
Solution
Reading the circuit, the steady-state voltage standing across the capacitor is 20 V and its capacitance is 10μF. The stored charge is then q=CV=10μF×20V=200μC.
JEE Main · 2019 · 09 Apr 2019 · Shift 1 · Single correct option