The degenerate orbitals of $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ are:

(A) $\mathrm{d}_{\mathrm{xz}}$ and $\mathrm{d}_{\mathrm{yz}}$

(B) $d_{x^{2}-y^{2}}$ and $d_{x y}$

(C) $\mathrm{d}_{\mathrm{yz}}$ and $\mathrm{d}_{\mathrm{z}^{2}}$

(D) $\mathrm{d}_{\mathrm{z}^{2}}$ and $\mathrm{d}_{\mathrm{xz}}$

JEE Main · 2019 · 09 Apr 2019 · Shift 1 · Coordination Compounds

The degenerate orbitals of

[Cr (H_{2} O)_{6}]^{3 +}

are:

(A) $d_{xz}$ and $d_{yz}$ ✓ Correct
(B) $d_{x^{2} - y^{2}}$ and $d_{x y}$
(C) $d_{yz}$ and $d_{z^{2}}$
(D) $d_{z^{2}}$ and $d_{xz}$

Answer: (A)

Solution

In the octahedral

[Cr (H X_{2} O) X_{6}]^{3 +}

the five d-orbitals split into a lower

t_{2 g}

set,

d_{x y}

d_{x z}

d_{y z}

, and an upper

e_{g}

set,

d_{z^{2}}

and

d_{x^{2} - y^{2}}

. Orbitals within one set share the same energy. Of the pairs offered,

d_{x z}

and

d_{y z}

both belong to

t_{2 g}

, so they are the degenerate pair.

JEE Main · 2019 · 09 Apr 2019 · Shift 1 · Single correct option

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