The circuit shown below contains two ideal diodes, each with a forward resistance of $50 \Omega$. If the battery voltage is 6 V , the current through the $100 \Omega$ resistance (in Amperes) is:

JEE Main · 2019 · 11 Jan 2019 · Shift 2 · Current Electricity

The circuit shown below contains two ideal diodes, each with a forward resistance of

50Ω

. If the battery voltage is 6 V , the current through the

100Ω

resistance (in Amperes) is:

(A)0.036
(B)0.020✓ Correct
(C)0.027
(D)0.030

Answer: (B)

Solution

With two ideal diodes in the network, one is forward biased and the other reverse biased. The reverse-biased diode blocks its branch completely, behaving as an open circuit that carries no current, so current flows only through the forward-biased path. There the diode adds its forward resistance of

50 Ω

in series with the

100 Ω

and

150 Ω

resistors, giving a total of

50 + 100 + 150 = 300 Ω

. The current through the

100 Ω

resistor is then

I = \frac{6}{300} = 0.02

JEE Main · 2019 · 11 Jan 2019 · Shift 2 · Single correct option

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