In the figure shown below, the charge on the left plate of the $10\,\mu\mathrm{F}$ capacitor is $-30\,\mu\mathrm{C}$. The charge on the right plate of the $6\,\mu\mathrm{F}$ capacitor is:

JEE Main · 2019 · 11 Jan 2019 · Shift 1 · Capacitance

In the figure shown below, the charge on the left plate of the

10 μ F

capacitor is

- 30 μ C

. The charge on the right plate of the

6 μ F

capacitor is:

(A) $- 12 μ C$
(B) $+ 12 μ C$
(C) $- 18 μ C$
(D) $+ 18 μ C$ ✓ Correct

Answer: (D)

Solution

The

10 μ F

capacitor is in series with the parallel pair of

6 μ F

and

4 μ F

, so the magnitude of charge on its plate,

30 μ C

, is the whole charge that reaches the parallel section. That charge divides in proportion to capacitance, so the

6 μ F

capacitor receives

\frac{6}{10} \times 30 = 18 μ C

, and as its negative plate faces the source the right plate carries

+ 18 μ C

JEE Main · 2019 · 11 Jan 2019 · Shift 1 · Single correct option

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