Two particles A,B are moving on two concentric circles of radii R1 and R2 with equal angular speed ω. At t=0, their positions and direction of motion are shown in the figure :
The relative velocity VA−VB at t=2ωπ is given by :
(A)ω(R1+R2)i^
(B)−ω(R1+R2)i^
(C)ω(R2−R1)i^✓ Correct
(D)ω(R1−R2)i^
Answer: (C)
Solution
After a time t=2ωπ each particle has turned through ωt=2π, a quarter circle. Both then sit on the positive y-axis moving in the −x direction, with vA=−ωR1i^ and vB=−ωR2i^. The relative velocity is vA−vB=−ωR1i^+ωR2i^=ω(R2−R1)i^.
JEE Main · 2019 · 12 Jan 2019 · Shift 2 · Single correct option