Temperature difference of 120∘C is maintained between two ends of a uniform rod AB of length 2L. Another bent rod PQ, of same cross-section as AB and length 23L, is connected across AB (See figure). In steady state, temperature difference between P and Q will be close to:
(A)45∘C✓ Correct
(B)75∘C
(C)60∘C
(D)35∘C
Answer: (A)
Solution
Model the rods as thermal resistors whose resistance is proportional to length. The bent rod PQ bridges the stretch of AB between its two contact points, so the two sit in parallel there, and in steady state the full 120∘C drop distributes across the series-parallel network in proportion to the resistances. Carrying the lengths through that division, with AB=2L and PQ=23L, places the temperature difference between P and Q at close to 120×83=45∘C.
JEE Main · 2019 · 09 Jan 2019 · Shift 1 · Single correct option