JEE Main · 2019 · 09 Jan 2019 · Shift 1 · Surface Chemistry

Adsorption of a gas follows Freundlich adsorption isotherm. In the given plot, x is the mass of gas adsorbed on mass

m

of the adsorbent at pressure

p

\frac{x}{m}

is proportional to

Answer: (C)

Solution

The Freundlich isotherm is

\frac{x}{m} = K p^{1/ n}

, so plotting

lo g \frac{x}{m}

against

lo g p

yields a straight line of slope

\frac{1}{n}

. The plot reads off a slope of

\frac{2}{4} = \frac{1}{2}

, so

\frac{x}{m} \propto p^{1/2}

JEE Main · 2019 · 09 Jan 2019 · Shift 1 · Single correct option