JEE Main · 2017 · 02 Apr 2017 · Offline · Current Electricity

When a current of 5 mA is passed through a galvanometer having a coil of resistance

15 Ω

, it shows full scale deflection. The value of the resistance to be put in series with the galvanometer to convert it into a voltmeter of range 0-10 V is:

(A) $2.535 \times 1 0^{3} Ω$
(B) $4.005 \times 1 0^{3} Ω$
(C) $1.985 \times 1 0^{3} Ω$ ✓ Correct
(D) $2.045 \times 1 0^{3} Ω$

Answer: (C)

Solution

A galvanometer turns into a voltmeter by adding a large series resistance so the full-scale current drops the entire range across the pair:

V = I_{g} (G + R)

. Here

10 = 5 \times 1 0^{- 3} (15 + R)

, so

15 + R = 2000

and

R = 1985 Ω

, that is

1.985 \times 1 0^{3} Ω

JEE Main · 2017 · 02 Apr 2017 · Offline · Single correct option

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