JEE Main · 2017 · 02 Apr 2017 · Offline · Current Electricity

In the given circuit diagram when the current reaches steady state in the circuit, the charge on the capacitor of capacitance C will be :

Answer: (A)

Solution

Once the circuit reaches steady state the capacitor is fully charged and its branch carries no current. The surviving current runs through

r

and

r_{2}

in series, and the capacitor sits across

r_{2}

, so it reads

V = E \frac{r _{2}}{r + r _{2}}

. Its charge is then

Q = C V = C E \frac{r _{2}}{r + r _{2}}

JEE Main · 2017 · 02 Apr 2017 · Offline · Single correct option