Given $\mathrm{E}_{\mathrm{Cr}^{3+} / \mathrm{Cr}}^{0}=-0.74 \mathrm{~V} ; \mathrm{E}_{\mathrm{MnO}_{4}^{-} / \mathrm{Mn}^{2+}}^{0}=1.51 \mathrm{~V}$ $\mathrm{E}_{\mathrm{Cr}_{2} \mathrm{O}_{7}^{-} / \mathrm{Cr}^{3+}}^{0}=1.33 \mathrm{~V} ; \mathrm{E}_{\mathrm{Cl} / \mathrm{Cl}^{-}}^{0}=1.36 \mathrm{~V}$ Based on the data given above, strongest oxidising agent will be:

JEE Main · 2013 · 07 Apr 2013 · Offline · Redox Reactions and Electrochemistry

Given

E_{Cr^{3 +} / Cr}^{0} = - 0.74 V; E_{MnO_{4}^{-} / Mn^{2 +}}^{0} = 1.51 V

E_{Cr_{2} O_{7}^{-} / Cr^{3 +}}^{0} = 1.33 V; E_{Cl / Cl^{-}}^{0} = 1.36 V

Based on the data given above, strongest oxidising agent will be:

(A) $Cr^{3 +}$
(B) $Mn^{2 +}$
(C) $MnO_{4}^{-}$ ✓ Correct
(D) $Cl^{-}$

Answer: (C)

Solution

The strongest oxidising agent is whichever species is most readily reduced, which means the highest standard reduction potential. Of the values given,

MnO X_{4} X^{-}

sits highest at

1.51 V

, so permanganate is the strongest oxidising agent on the list.

JEE Main · 2013 · 07 Apr 2013 · Offline · Single correct option

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