The molecular shapes of $\mathrm{SF}_{4}, \mathrm{CF}_{4}$ and $\mathrm{XeF}_{4}$ are

(D) different with 1,0 and 2 lone pairs of electron on the central atoms respectively

(A) the same with 2,0 and 1 lone pairs of electrons on the central atom, respectively

(B) the same with 1, 1 and 1 lone pair of electrons on the central atoms, respectively

(C) different with 0 , 1 and 2 lone pair of electrons on the central atoms, respectively

JEE Main · 2005 · 08 May 2005 · Offline · Chemical Bonding and Molecular Structure

The molecular shapes of

SF_{4}, CF_{4}

and

XeF_{4}

are

(A)the same with 2,0 and 1 lone pairs of electrons on the central atom, respectively
(B)the same with 1, 1 and 1 lone pair of electrons on the central atoms, respectively
(C)different with 0 , 1 and 2 lone pair of electrons on the central atoms, respectively
(D)different with 1,0 and 2 lone pairs of electron on the central atoms respectively✓ Correct

Answer: (D)

Solution

These three fluorides are built on different numbers of lone pairs, so their shapes differ. Sulphur in

SF X_{4}

keeps one lone pair and takes a see-saw shape; carbon in

CF X_{4}

has no lone pair and is tetrahedral; xenon in

XeF X_{4}

holds two lone pairs and is square planar. With lone-pair counts of one, zero and two running in that order, the three molecular shapes are all different.

JEE Main · 2005 · 08 May 2005 · Offline · Single correct option

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JEE Main · 2005 · 08 May 2005 · Offline · Chemical Bonding and Molecular Structure

Solution

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