Which among the following factors is the most important in making fluorine the strongest oxidizing halogen?
- (A)Electron affinity
- (B)Bond dissociation energy✓ Correct
- (C)Hydration enthalpy
- (D)Ionization enthalpy
Answer: (B)
Solution
Fluorine's standing as the strongest oxidising halogen rests chiefly on its unusually weak bond, whose low dissociation energy comes from the strong repulsion between the two small, electron-crowded fluorine atoms. Breaking that bond costs little, and together with the large hydration enthalpy of the small ion it makes the overall reduction highly favourable. Electron affinity and hydration help, but it is the low bond dissociation energy that counts most.
JEE Main · 2004 · 24 Apr 2004 · Offline · Single correct option