JEE Main · 2004 · 24 Apr 2004 · Offline · Coordination Compounds

Which one of the following complexes in an outer orbital complex?

(A) $[Fe (CN)_{6}]^{4 -}$
(B) $[Ni (NH_{3})_{6}]^{2 +}$ ✓ Correct
(C) $[Co (NH_{3})_{6}]^{3 +}$
(D) $[Mn (CN)_{6}]^{4 -}$

Answer: (B)

Solution

An outer-orbital complex uses the metal's outer d orbitals in its hybridisation, which happens with weak-field ligands. In

[Ni (NH X_{3}) X_{6}] X^{2 +}

the nickel is

d^{8}

and ammonia is a weak-field ligand, so the bonding is

s p^{3} d^{2}

using the outer d set, making it an outer-orbital octahedral complex. The cyanide complexes, with their strong-field ligand, are inner-orbital instead.

JEE Main · 2004 · 24 Apr 2004 · Offline · Single correct option

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