Number of moles and number of molecules in 1.4187 L of $\ce{SO2}$ at STP respectively are

(B) $0.0633; 3.812 \times 10^{22}$

(A) $0.1266; 3.812 \times 10^{22}$

(C) $0.1266; 7.6238 \times 10^{22}$

(D) $0.0633; 7.6238 \times 10^{22}$

JEE Main · 2026 · 04 Apr 2026 · Shift 1 · Some Basic Concepts of Chemistry

Number of moles and number of molecules in 1.4187 L of

SO X_{2}

at STP respectively are

Answer: (B)

Taking the molar volume at STP as

22.4 L

, the amount of gas is

n = \frac{1.4187}{22.4} = 0.0633 mol

. The number of molecules is

0.0633 \times 6.022 \times 1 0^{23} = 3.812 \times 1 0^{22}

. Hence the sample holds

0.0633

mol and

3.812 \times 1 0^{22}

molecules.

JEE Main · 2026 · 04 Apr 2026 · Shift 1 · Single correct option