Given below are two statements : Statement-I : Presence of large number of unpaired electrons in transition metal atoms results in higher enthalpies of their atomisation. Statement-II : \(\mathrm{d}_{\mathrm{xy}}=\mathrm{d}_{\mathrm{xz}}=\mathrm{d}_{\mathrm{yz}}<\mathrm{d}_{\mathrm{x}^{2}-\mathrm{y}^{2}}=\mathrm{d}_{\mathrm{z}^{2}}\) and \(\mathrm{d}_{\mathrm{x}^{2}-\mathrm{y}^{2}}=\mathrm{d}_{\mathrm{z}^{2}}<\mathrm{d}_{\mathrm{xy}}=\mathrm{d}_{\mathrm{xz}}=\mathrm{d}_{\mathrm{yz}}\) are the d-orbital splittings in \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) and \(\left[\mathrm{Ni}(\mathrm{Cl})_{4}\right]^{2-}\) complex ions respectively. In the light of the above statements, choose the correct answer from the options given below :

(A) Both Statement-I and Statement-II are correct.

(B) Both Statement-I and Statement-II are incorrect.

(C) Statement-I is correct but Statement-II is incorrect.

(D) Statement-I is incorrect but Statement-II is correct.

JEE Main · 2026 · 05 Apr 2026 · Shift 2 · Coordination Compounds

Given below are two statements :

Statement-I : Presence of large number of unpaired electrons in transition metal atoms results in higher enthalpies of their atomisation.

Statement-II :

d_{xy} = d_{xz} = d_{yz} < d_{x^{2} - y^{2}} = d_{z^{2}}

and

d_{x^{2} - y^{2}} = d_{z^{2}} < d_{xy} = d_{xz} = d_{yz}

are the d-orbital splittings in

[Fe (H_{2} O)_{6}]^{3 +}

and

[Ni (Cl)_{4}]^{2 -}

complex ions respectively.

In the light of the above statements, choose the correct answer from the options given below :

(A)Both Statement-I and Statement-II are correct.✓ Correct
(B)Both Statement-I and Statement-II are incorrect.
(C)Statement-I is correct but Statement-II is incorrect.
(D)Statement-I is incorrect but Statement-II is correct.

Answer: (A)

Solution

A transition metal with more unpaired

d

electrons forms stronger metal--metal bonds in the solid, raising its enthalpy of atomisation, so Statement-I is correct. In the octahedral ion

[Fe (H_{2} O)_{6}]^{3 +}

the

t_{2g}

orbitals

(d_{xy} = d_{xz} = d_{yz})

lie below the

e_{g}

orbitals

(d_{x^{2} - y^{2}} = d_{z^{2}})

, matching the first splitting; in the tetrahedral ion

[NiC l_{4}]^{2 -}

the

e

orbitals

(d_{x^{2} - y^{2}} = d_{z^{2}})

lie below the

t_{2}

orbitals

(d_{xy} = d_{xz} = d_{yz})

, matching the second splitting, so Statement-II is correct. Both Statement-I and Statement-II are correct.

JEE Main · 2026 · 05 Apr 2026 · Shift 2 · Single correct option

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JEE Main · 2026 · 05 Apr 2026 · Shift 2 · Coordination Compounds

Solution

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