JEE Main · 2026 · 06 Apr 2026 · Shift 1 · General Organic Chemistry

2,6-Diethylcyclohexanone and 6-methyl-2-$n$-propylcyclohexanone both have the molecular formula ${\mathrm{C}}_{10}{\mathrm{H}}_{18}\mathrm{O}$ and bear alkyl groups on the two carbons flanking the carbonyl, but the groups differ (two ethyls against a methyl and an $n$-propyl); different alkyl groups distributed about the same functional carbon make them metamers, so Statement-I is correct.

Keto-enol tautomerism requires an $\alpha$-hydrogen, yet in 2,2,6,6-tetramethylcyclohexanone both $\alpha$-carbons carry two methyl groups and no $\alpha$-hydrogen remains, so it cannot tautomerise and Statement-II is false.

Statement-I is true and Statement-II is false.