JEE Advanced · 2025 · 18 May 2025 · Paper 1 · Units & Measurement

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Figure 1 shows the configuration of main scale and Vernier scale before measurement. Fig. 2 shows the configuration corresponding to the measurement of diameter of a tube. The measured value of is:
Structure Fig. 1
Fig. 1
Structure Fig. 2
Fig. 2
  1. (A)0.12 cm
  2. (B)0.11 cm
  3. (C)0.13 cm✓ Correct
  4. (D)0.14 cm

Answer: (C)

Solution

From the figures:
  • 10 MSD = 1 cm, so 1 MSD = 0.1 cm
  • 7 MSD = 10 VSD, so 1 VSD = 0.07 cm

The reading is calculated as:
Reading = 2 MSD - VSD = 0.2 cm - 0.07 cm = 0.13 cm

Note: The negative sign accounts for the zero error shown in Fig. 1.

JEE Advanced · 2025 · 18 May 2025 · Paper 1 · Single correct option

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