Figure 1 shows the configuration of main scale and Vernier scale before measurement. Fig. 2 shows the configuration corresponding to the measurement of diameter D of a tube. The measured value of D is:Fig. 1Fig. 2
(A)0.12 cm
(B)0.11 cm
(C)0.13 cm✓ Correct
(D)0.14 cm
Answer: (C)
Solution
From the figures:
10 MSD = 1 cm, so 1 MSD = 0.1 cm
7 MSD = 10 VSD, so 1 VSD = 0.07 cm
The reading is calculated as: Reading = 2 MSD - VSD = 0.2 cm - 0.07 cm = 0.13 cm
Note: The negative sign accounts for the zero error shown in Fig. 1.
JEE Advanced · 2025 · 18 May 2025 · Paper 1 · Single correct option