JEE Advanced · 2025 · 18 May 2025 · Paper 1 · Units & Measurement

A single slit diffraction experiment is performed to determine the slit width using the equation, $\frac{bd}{D}=m\lambda$, where $b$ is the slit width, $D$ the shortest distance between the slit and the screen, $d$ the distance between the $m^{\text{th }}$ diffraction maximum and the central maximum, and $\lambda$ is the wavelength. $D$ and $d$ are measured with scales of least count of 1 cm and 1 mm, respectively. The values of $\lambda$ and $m$ are known precisely to be 600 nm and 3, respectively. The absolute error (in $\mu \mathrm{m}$ ) in the value of $b$ estimated using the diffraction maximum that occurs for $m=3$ with $d=5\mathrm{mm}$ and $D=1\mathrm{m}$ is ____.