JEE Advanced · 2024 · 26 May 2024 · Paper 2 · Surface Chemistry

To form a complete monolayer of acetic acid on 1g of charcoal, 100 mL of 0.5 M acetic acid was used. Some of the acetic acid remained unadsorbed. To neutralize the unadsorbed acetic acid, 40 mL of 1 M NaOH solution was required. If each molecule of acetic acid occupies $\mathbf{P}\times 10^{-23}{\mathrm{m}}^2$ surface area on charcoal, the value of $\mathbf{P}$ is ____.
[Use given data : Surface area of charcoal $=1.5\times 10^2{\mathrm{m}}^2{\mathrm{g}}^{-1}$; Avogadro's number $\left({\mathrm{N}}_{\mathrm{A}}\right)=6.0\times 10^{23}{\mathrm{mol}}^{-1}$ ]