Match the rate expressions in LIST-I for the decomposition of X with the corresponding profiles provided in LIST-II. Xs and k constants having appropriate units.
List-I (I) rate =Xs+[X]k[X] under all possible initial concentration of X (II) rate =Xs+[X]k[X] where initial concentration of X are much less than Xs (III) rate =Xs+[X]k[X] where initial concentration of X are much higher than Xs (IV) rate =Xs+[X]k[X]2 where initial concentration of X is much higher than Xs
List-II (P) (see graph) (Q) (see graph) (R) (see graph) (S) (see graph) (T) (see graph)PQRST
(A)I → P; II → Q; III → S; IV → T✓ Correct
(B)I → R; II → S; III → S; IV → T
(C)I → P; II → Q; III → Q; IV → R
(D)I → R; II → S; III → Q; IV → R
Answer: (A)
Solution
Analyzing each rate expression:
(I) When [X]→∞, rate →k (zero order). This matches profiles (P) or (R).
(II) When [X]≪Xs, rate =Xsk[X] (first order). This matches profiles (Q) or (T).
(III) When [X]≫Xs, rate →k (zero order). This matches profiles (P) or (S).
(IV) When [X]≫Xs, rate =k[X] (first order). This matches profiles (Q) or (T).
Based on the solution provided, the correct matching is: I → P (zero order at high concentration) II → Q (first order at low concentration) III → S (zero order at high concentration) IV → T (first order behavior)
Therefore, option (A) is correct.
JEE Advanced · 2022 · 28 Aug 2022 · Paper 1 · Single correct option
