JEE Advanced · 2021 · 03 Oct 2021 · Paper 2 · Chemical Thermodynamics

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The amount of energy required to break a bond is same as the amount of energy released when the same bond is formed. In gaseous state, the energy required for homolytic cleavage of a bond is called Bond Dissociation Energy (BDE) or Bond Strength. BDE is affected by -character of the bond and the stability of the radicals formed. Shorter bonds are typically stronger bonds. BDEs for some bonds are given below :


For the following reaction

the correct statement is
  1. (A)Initiation step is exothermic with
  2. (B)Propagation step involving formation is exothermic with
  3. (C)Propagation step involving formation is endothermic with
  4. (D)The reaction is exothermic with .✓ Correct

Answer: (D)

Solution

Calculate for the overall reaction using bond energies. Bonds broken: (+105 kcal/mol) and (+58 kcal/mol). Bonds formed: (−85 kcal/mol) and (−103 kcal/mol). kcal/mol. The reaction is exothermic. (A) Initiation () is endothermic (+58). (B) Propagation forming () has kcal/mol (endothermic). (C) Propagation forming () has kcal/mol (exothermic). Only (D) is correct.

JEE Advanced · 2021 · 03 Oct 2021 · Paper 2 · Single correct option

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