JEE Advanced · 2019 · 27 May 2019 · Paper 2 · Waves & Sound

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A musical instrument is made using four different metal strings, 1,2,3 and 4 with mass per unit length and respectively. The instrument is played by vibrating the strings by varying the free length in between the range and . It is found that in string-1 at free length and tension the fundamental mode frequency is .

List-I gives the above four strings while list-II lists the magnitude of some quantity.

List-I
(I) String-1
(II) String-2
(III) String-3
(IV) String-4

List-II
(P) 1
(Q) 1/2
(R)
(S)
(T) 3/16
(U) 1/16

The length of the string 1,2,3 and 4 are kept fixed at and , respectively. Strings 1,2,3 and 4 are vibrated at their and harmonics, respectively such that all the strings have same frequency. The correct match for the tension in the four strings in the units of will be.
  1. (A)I→P, II→Q, III→T, IV→U✓ Correct
  2. (B)I→T, II→Q, III→R, IV→U
  3. (C)I→P, II→Q, III→R, IV→T
  4. (D)I→P, II→R, III→T, IV→U

Answer: (A)

Solution

For string 1 (length , 1st harmonic):

With → (P)

For string 2 (length , 3rd harmonic):

Comparing with string 1: → (Q)

For string 3 (length , 5th harmonic):

Solving: → (T)

For string 4 (length , 14th harmonic):

Solving: → (U)

Therefore: I→P, II→Q, III→T, IV→U

JEE Advanced · 2019 · 27 May 2019 · Paper 2 · Single correct option

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