JEE Advanced · 2018 · 20 May 2018 · Paper 1 · Chemical Thermodynamics

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A closed tank has two compartments A and B, both filled with oxygen (assumed to be ideal gas). The partition separating the two compartments is fixed and is a perfect heat insulator (Figure 1). If the old partition is replaced by a new partition which can slide and conduct heat but does NOT allow the gas to leak across (Figure 2), the volume (in

m^{3}

) of the compartment A after the system attains equilibrium is ____.

Answer: 2.22

Solution

Figure 1: compartment A

= 1

^{3}

5

bar,

400

K; compartment B

= 3

^{3}

1

bar,

300

K (total

4

^{3}

). With a sliding, heat-conducting partition both sides reach a common pressure and temperature while A keeps its mole count. Applying

\frac{P _{i} V _{i}}{T _{i}} = \frac{P _{f} V _{f}}{T _{f}}

for A together with mechanical and thermal equilibrium gives

V_{A} \approx 2.22

^{3}

. Official answer [2.22].

JEE Advanced · 2018 · 20 May 2018 · Paper 1 · Numerical answer

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JEE Advanced · 2018 · 20 May 2018 · Paper 1 · Chemical Thermodynamics

Solution

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