Three moles of B₂H₆ are completely reacted with methanol. The number of moles of boron containing product formed is
Answer: 6
Solution
The reaction is:
B₂H₆ + 6CH₃OH → 2B(OCH₃)₃ + 6H₂
From 1 mole of B₂H₆, 2 moles of B(OCH₃)₃ are formed.
From 3 moles of B₂H₆, moles of boron-containing product = 3 × 2 = 6 moles.
B₂H₆ + 6CH₃OH → 2B(OCH₃)₃ + 6H₂
From 1 mole of B₂H₆, 2 moles of B(OCH₃)₃ are formed.
From 3 moles of B₂H₆, moles of boron-containing product = 3 × 2 = 6 moles.
JEE Advanced · 2015 · 24 May 2015 · Paper 2 · Integer answer