The correct statement(s) regarding, (i) HClO, (ii) HClO₂, (iii) HClO₃ and (iv) HClO₄, is(are)
- (A)The number of Cl=O bonds in (ii) and (iii) together is two
- (B)The number of lone pairs of electrons on Cl in (ii) and (iii) together is three✓ Correct
- (C)The hybridization of Cl in (iv) is sp³✓ Correct
- (D)Amongst (i) to (iv), the strongest acid is (i)
Answer: (B), (C)
Solution
Analyzing each statement:
(A) HClO₂ has 1 Cl=O bond, HClO₃ has 2 Cl=O bonds. Total = 3, not 2. Incorrect.
(B) HClO₂ has 2 lone pairs on Cl, HClO₃ has 1 lone pair on Cl. Total = 3. Correct.
(C) In HClO₄, Cl is bonded to 4 oxygen atoms (3 double bonds and 1 single bond with OH). The hybridization is sp³. Correct.
(D) Acid strength increases with the number of oxygen atoms: HClO < HClO₂ < HClO₃ < HClO₄. The strongest is HClO₄, not HClO. Incorrect.
Correct options: (B) and (C).
(A) HClO₂ has 1 Cl=O bond, HClO₃ has 2 Cl=O bonds. Total = 3, not 2. Incorrect.
(B) HClO₂ has 2 lone pairs on Cl, HClO₃ has 1 lone pair on Cl. Total = 3. Correct.
(C) In HClO₄, Cl is bonded to 4 oxygen atoms (3 double bonds and 1 single bond with OH). The hybridization is sp³. Correct.
(D) Acid strength increases with the number of oxygen atoms: HClO < HClO₂ < HClO₃ < HClO₄. The strongest is HClO₄, not HClO. Incorrect.
Correct options: (B) and (C).
JEE Advanced · 2015 · 24 May 2015 · Paper 2 · One or more correct options