The reactions of $\mathrm{Cl}_{2}$ gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two (different) oxoacids of chlorine, $\boldsymbol{P}$ and $\boldsymbol{Q}$, respectively. The $\mathrm{Cl}_{2}$ gas reacts with $SO_{2}$ gas, in presence of charcoal, to give a product $\boldsymbol{R}$. $\boldsymbol{R}$ reacts with white phosphorus to give a compound $\boldsymbol{S}$. On hydrolysis, $\boldsymbol{S}$ gives an oxoacid of phosphorus, $T$. $R, S$ and $T$, respectively, are

(A) $\mathrm{SO}_{2} \mathrm{Cl}_{2}, \mathrm{PCl}_{5}$ and $\mathrm{H}_{3} \mathrm{PO}_{4}$

(B) $\mathrm{SO}_{2} \mathrm{Cl}_{2}, \mathrm{PCl}_{3}$ and $\mathrm{H}_{3} \mathrm{PO}_{3}$

(C) $\mathrm{SOCl}_{2}, \mathrm{PCl}_{3}$ and $\mathrm{H}_{3} \mathrm{PO}_{2}$

(D) $\mathrm{SOCl}_{2}, \mathrm{PCl}_{5}$ and $\mathrm{H}_{3} \mathrm{PO}_{4}$

JEE Advanced · 2013 · 02 Jun 2013 · Paper 2 · p-Block Elements

The reactions of

Cl_{2}

gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two (different) oxoacids of chlorine,

P

and

Q

, respectively. The

Cl_{2}

gas reacts with

S O_{2}

gas, in presence of charcoal, to give a product

R

R

reacts with white phosphorus to give a compound

S

. On hydrolysis,

S

gives an oxoacid of phosphorus,

T

R, S

and

T

, respectively, are

Answer: (A)

SO_{2} + Cl_{2} Charcoal SO_{2} Cl_{2}

(sulfuryl chloride,

R

)

SO_{2} Cl_{2} + P_{4} \to PCl_{5} + SO_{2}

(

S = PCl_{5}

)

PCl_{5} + 4 H_{2} O \to H_{3} PO_{4} + 5 HCl

(

T = H_{3} PO_{4}

)

So

R, S, T

are

SO_{2} Cl_{2}, PCl_{5}, H_{3} PO_{4}

JEE Advanced · 2013 · 02 Jun 2013 · Paper 2 · Single correct option