JEE Advanced · 2013 · 02 Jun 2013 · Paper 2 · Hydrocarbons

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Match the chemical conversions in List I with the appropriate reagents in List II and select the correct answer using the code given below the lists:
List II
1.(i) ; (ii)
2.NaOEt
3.Et-Br
4.(i) ; (ii)
  1. (A)P-2, Q-3, R-1, S-4✓ Correct
  2. (B)P-3, Q-2, R-1, S-4
  3. (C)P-2, Q-3, R-4, S-1
  4. (D)P-3, Q-2, R-4, S-1

Answer: (A)

Solution

Matching the conversions with reagents:

P: Elimination reaction (E2) → NaOEt (2)

Q: Williamson ether synthesis → Et-Br (3)

R: Oxymercuration-demercuration (Markovnikov addition) → (i) ; (ii) (1)

S: Hydroboration-oxidation (anti-Markovnikov addition) → (i) ; (ii) (4)

Code: P-2, Q-3, R-1, S-4

JEE Advanced · 2013 · 02 Jun 2013 · Paper 2 · Single correct option

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