For the resistance network shown in the figure, choose the correct option(s).
(A)The current through PQ is zero.✓ Correct
(B)I1=3A.✓ Correct
(C)The potential at S is less than that at Q.✓ Correct
(D)I2=2A.✓ Correct
Answer: (A), (B), (C), (D)
Solution
The network forms a Wheatstone bridge with nodes P and Q equipotential, and nodes S and T equipotential. No current flows through PQ or ST. The current I1=412=3 A. The current I2=I1×6+1212=3×1812=2 A. The potential at S is less than at Q due to the voltage drop. All options are correct.
JEE Advanced · 2012 · 08 Apr 2012 · Paper 1 · One or more correct options