A student is performing the experiment of Resonance Column. The diameter of the column tube is 4 cm . The frequency of the tuning fork is 512 Hz . The air temperature is \(38^{\circ} \mathrm{C}\) in which the speed of sound is 336 m/s. The zero of the meter scale coincides with the top end of the Resonance Column tube. When the first resonance occurs, the reading of the water level in the column is

JEE Advanced · 2012 · 08 Apr 2012 · Paper 2 · Waves & Sound

A student is performing the experiment of Resonance Column. The diameter of the column tube is 4 cm . The frequency of the tuning fork is 512 Hz . The air temperature is

3 8^{\circ} C

in which the speed of sound is 336 m/s. The zero of the meter scale coincides with the top end of the Resonance Column tube. When the first resonance occurs, the reading of the water level in the column is

(A)14.0 cm
(B)15.2 cm✓ Correct
(C)16.4 cm
(D)17.6 cm

Answer: (B)

Solution

For the first resonance in a closed pipe,

L + e = \frac{λ}{4}

, where

e

is the end correction. The wavelength

λ = \frac{v}{f} = \frac{336}{512} = 0.65625

m = 65.625 cm. The end correction

e \approx 0.3 d = 0.3 \times 4 = 1.2

cm. Therefore,

L = \frac{λ}{4} - e = \frac{65.625}{4} - 1.2 = 16.406 - 1.2 = 15.2

cm.

JEE Advanced · 2012 · 08 Apr 2012 · Paper 2 · Single correct option

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JEE Advanced · 2012 · 08 Apr 2012 · Paper 2 · Waves & Sound

Solution

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