JEE Advanced · 2011 · 10 Apr 2011 · Paper 1 · Current Electricity

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A meter bridge is set-up as shown, to determine an unknown resistance 'X' using a standard 10 ohm resistor. The galvanometer shows null point when tapping-key is at 52 cm mark. The end-corrections are 1 cm and 2 cm respectively for the ends A and B. The determined value of 'X' is

(A)10.2 ohm
(B)10.6 ohm✓ Correct
(C)10.8 ohm
(D)11.1 ohm

Answer: (B)

Solution

In a meter bridge at null point:

\frac{X}{R} = \frac{l _{1}}{l _{2}}

With end corrections, the effective lengths are:

Length on X side: $52 + 1 = 53$ cm
Length on R side: $(100 - 52) + 2 = 50$ cm

\frac{X}{10} = \frac{53}{50}

X = 10 \times \frac{53}{50} = 10.6 ohm

JEE Advanced · 2011 · 10 Apr 2011 · Paper 1 · Single correct option

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