A decapeptide (Mol. Wt. 796) on complete hydrolysis gives glycine (Mol. Wt. 75), alanine and phenylalanine. Glycine contributes 47.0 % to the total weight of the hydrolysed products. The number of glycine units present in the decapeptide is
Answer: 6
Solution
When a decapeptide (10 amino acids) is hydrolyzed, 9 water molecules are added.
Total weight of hydrolyzed products = 796 + 9 × 18 = 796 + 162 = 958 g/mol
Weight of glycine in products = 47% of 958 = 0.47 × 958 = 450.26 g
Number of glycine units =
Therefore, the number of glycine units = 6
Total weight of hydrolyzed products = 796 + 9 × 18 = 796 + 162 = 958 g/mol
Weight of glycine in products = 47% of 958 = 0.47 × 958 = 450.26 g
Number of glycine units =
Therefore, the number of glycine units = 6
JEE Advanced · 2011 · 10 Apr 2011 · Paper 1 · Integer answer