The ionization isomer of $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4} \mathrm{Cl}\left(\mathrm{NO}_{2}\right)\right] \mathrm{Cl}$ is

(B) $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4} \mathrm{Cl}_{2}\right]\left(\mathrm{NO}_{2}\right)$

(A) $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\left(\mathrm{O}_{2} \mathrm{~N}\right)\right] \mathrm{Cl}_{2}$

(C) $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4} \mathrm{Cl}(\mathrm{ONO})\right] \mathrm{Cl}$

(D) $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4} \mathrm{Cl}_{2}\left(\mathrm{NO}_{2}\right)\right] \cdot \mathrm{H}_{2} \mathrm{O}$

JEE Advanced · 2010 · 11 Apr 2010 · Paper 1 · Coordination Compounds

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The ionization isomer of

[Cr (H_{2} O)_{4} Cl (NO_{2})] Cl

(A) $[Cr (H_{2} O)_{4} (O_{2} N)] Cl_{2}$
(B) $[Cr (H_{2} O)_{4} Cl_{2}] (NO_{2})$ ✓ Correct
(C) $[Cr (H_{2} O)_{4} Cl (ONO)] Cl$
(D) $[Cr (H_{2} O)_{4} Cl_{2} (NO_{2})] \cdot H_{2} O$

Answer: (B)

Solution

Ionization isomers differ in the ions produced when dissolved in solution. In the original complex

[Cr (H_{2} O)_{4} Cl (NO_{2})] Cl

, one Cl⁻ is outside the coordination sphere (counter ion) and NO₂⁻ is inside. In the ionization isomer, these swap positions: NO₂⁻ becomes the counter ion and Cl⁻ enters the coordination sphere, giving

[Cr (H_{2} O)_{4} Cl_{2}] (NO_{2})

JEE Advanced · 2010 · 11 Apr 2010 · Paper 1 · Single correct option

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JEE Advanced · 2010 · 11 Apr 2010 · Paper 1 · Coordination Compounds

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