In the reaction \[ 2 \mathbf{X}+\mathrm{B}_{2} \mathrm{H}_{6} \rightarrow\left[\mathrm{BH}_{2}(\mathbf{X})_{2}\right]^{+}\left[\mathrm{BH}_{4}\right]^{-} \] the amine(s) $\mathbf{X}$ is(are)

(A) $\mathrm{NH}_{3}$; (B) $\mathrm{CH}_{3} \mathrm{NH}_{2}$; (C) $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}$

(D) $\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}$

JEE Advanced · 2009 · 12 Apr 2009 · Paper 2 · p-Block Elements

In the reaction

2 X + B_{2} H_{6} \to [BH_{2} (X)_{2}]^{+} [BH_{4}]^{-}

the amine(s)

X

is(are)

Answer: (A), (B), (C)

Diborane reacts with amines to form adducts. However, trimethylamine

(CH_{3})_{3} N

is too bulky to react in this manner due to steric hindrance. The less bulky amines

NH_{3}

CH_{3} NH_{2}

, and

(CH_{3})_{2} NH

can all participate in this reaction.

JEE Advanced · 2009 · 12 Apr 2009 · Paper 2 · One or more correct options