JEE Advanced · 2009 · 12 Apr 2009 · Paper 2 · Waves & Sound

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A 20 cm long string, having a mass of 1.0 g, is fixed at both the ends. The tension in the string is 0.5 N. The string is set into vibrations using an external vibrator of frequency 100 Hz . Find the separation (in cm) between the successive nodes on the string.

Answer: 5

Solution

The wave speed on the string is , where kg/m. Thus m/s. The wavelength is m = 10 cm. The separation between successive nodes is cm.

JEE Advanced · 2009 · 12 Apr 2009 · Paper 2 · Integer answer

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