In the given figure an ammeter A consists of a 240Ω coil connected in parallel to a 10Ω shunt. The reading of the ammeter is ______ mA.
Answer: 160
Solution
The ammeter's coil (240Ω) and shunt (10Ω) are in parallel: Req=250240×10=9.6Ω. In series with 140.4Ω and a 24 V source, total resistance =140.4+9.6=150Ω. The current the ammeter reads is I=15024=0.16 A=160 mA.