The number of unpaired d-electrons in [Co(H2O)6]3+ is
(A)4
(B)2
(C)0✓ Correct
(D)1
Answer: (C)
Solution
Co3+ has a d6 configuration. Despite H2O being only a moderately strong field ligand in general, the high charge on Co3+ increases the crystal field splitting enough that [Co(H2O)6]3+ is experimentally low-spin: t2g6eg0. All six d-electrons are paired in the t2g set, so there are 0 unpaired electrons.Electronic configuration diagram
JEE Main · 2024 · 04 Apr 2024 · Shift 2 · Single correct option