For the compounds: (A) $\mathrm{H}_{3} \mathrm{C}-\mathrm{CH}_{2}-\mathrm{O}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{3}$ (B) $\mathrm{H}_{3} \mathrm{C}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{3}$ (C) (see structure) (D) (see structure) The increasing order of boiling point is : Choose the correct answer from the options given below :

(B) (B) $<$ (A) $<$ (C) $<$ (D)

(A) (A) $<$ (B) $<$ (C) $<$ (D)

(C) (D) $<$ (C) $<$ (A) $<$ (B)

(D) (B) $<$ (A) $<$ (D) $<$ (C)

JEE Main · 2024 · 05 Apr 2024 · Shift 1 · Chemical Bonding and Molecular Structure

For the compounds:
(A)

H_{3} C - CH_{2} - O - CH_{2} - CH_{2} - CH_{3}

(B)

H_{3} C - CH_{2} - CH_{2} - CH_{2} - CH_{3}

(C) (see structure)
(D) (see structure)

The increasing order of boiling point is :
Choose the correct answer from the options given below :

(A)(A) $<$ (B) $<$ (C) $<$ (D)
(B)(B) $<$ (A) $<$ (C) $<$ (D)✓ Correct
(C)(D) $<$ (C) $<$ (A) $<$ (B)
(D)(B) $<$ (A) $<$ (D) $<$ (C)

Answer: (B)

Solution

All four compounds have the same number of carbons, so boiling point follows the polarity/H-bonding order: non-polar < polar (ether) < ... < H-bonded (alcohol). Here (B)

n

-pentane (non-polar) is lowest, (A) the ether next, then (C) the ketone (higher polarity), and (D) the alcohol highest (intermolecular H-bonding). Increasing order: (B) < (A) < (C) < (D).

JEE Main · 2024 · 05 Apr 2024 · Shift 1 · Single correct option

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JEE Main · 2024 · 05 Apr 2024 · Shift 1 · Chemical Bonding and Molecular Structure

Solution

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